JAVA: My code works, but gives one result for all test cases.

Question

EDIT: SOLVED

This code counts how many numbers are there, whose digits summation is 19 or 19-multiple from 1 to the given input number, n. The program will then print how many numbers there are satisfying the condition mentioned above. n must be between 100 and 1000000 inclusive.

So if the input is 200, the output must be 1. From 1 to 200, there is only one number, whose digits add up to 19 or 19's multiple. This number is 199. This is because 1+9+9 = 19

My code only outputs the count as 0. I'm trying to find my mistake, but help is appreciated.

https://code.sololearn.com/cl4ZQ7QZM6W3

Answer 1

Salma D. Elabsi

What if sum is 114?

Do this instead of comparing with Hard Code value:

if(sum % 19 == 0)

You are not using i. You should assign i to a new variable then use that variable in while loop.

https://code.sololearn.com/cF9c68wUfq2z/?ref=app

Answer 2

In your code you are manipulating n. It gets 0 in your while loop so your for loop runs only one times.

Before you start your while loop:
int num = i; //Don't manipulate i because your for loop is working with it
sum = 0; //reset sum

Then your while loop where you just change n to num.