list of digit with mathematics operation (loop)

Question

context is, i want to split all number's digit like list, string function/method with loop and math operator

solution is:
1) let's say we want to separate this number 123 with % operator by 10. like this, we will get last digit of number
>>> x = 123
>>> a = x % 10 (get 3)

2) Divide the number you want to split by 10 to get only integers (// operator)
>>> x = x // 10 (get 2)

3) bring the numbet from step 2 back to step 1
>>> b = x % 10 (12 % 10 = 2)

and repeat the loop

my code:
n = int(input("input number: "))
remain = n
digit = 0
result = ' '

while remain != 0:
degit = remain % 10
if result == ' ':
result = str(digit)
else:
result = str(digit) + ', ' + result

remain = remain // 10

print(f"list of digit: {result}")

input >>> 5678

#expected output
list of digit: 5, 6, 7, 8

#my output
list of digit: 0, 0, 0, 0

question is why my output is 0, 0, 0, 0. can someone correct my code please? i have no idea why ...

Answer 1

Maybe it is the little typo in the first line of your while loop
degit should be digit

Answer 2

Oma Falk oh thank you! I didn't spot this little mistake. thank you again!