Phone number validating

Question

I want to know why this code won’t work please
import re
x = (input())
if x[0] == 1:
print("Valid")
if x[0] == 8:
print("Valid")
if x[0] == 9:
print("Valid")
else:
print("Invalid")
Thank you :)

Answer 1

This is the code for your question
Jessica

x = input()
if (x[0] == "1" or x[0] == "8" or x[0] == "9") and len(x) == 8:
print("Valid")
else:
print("Invalid")

Answer 2

Muhammad okay thank you

Answer 3

You're welcome Jessica

Answer 4

What exactly is your code supposed to do? And why did you import re but never use it?

Answer 5

#to make it work properly (idk the task)

x = input()
if x[0] == "1":
print("Valid")
elif x[0] == "8":
print("Valid")
elif x[0] == "9":
print("Valid")
else:
print("Invalid")

Answer 6

Import re was already there but I don’t really know what it means!

Answer 7

You are given a number input, and need to check if it is a valid phone number.
A valid phone number has exactly 8 digits and starts with 1, 8 or 9.
Output "Valid" if the number is valid and "Invalid", if it is not.

Sample Input
81239870

Sample Output
Valid

Answer 8

re is imported without any reason.

also you are taking input as string.
just use
x = int(input())
then all values will be compared

Answer 9

That re(regular expression/regex) problem

Solution :

import re

def check(phno):
Pattern = re.compile("(0|91)?[7-9][0-9]{10}")
return Pattern.match(phno)

check(input())

"""and i would recommend you learn regex, instead of hard-coding, 👍"""

Answer 10

Second to last project in python thanks for helping me