code is given below. when I'm adding more items after running in loop it takes only first item in file and rest not. so please

Question

code is given below. when I'm adding more items after running in loop it takes only first item in file and rest not. so please help me.
thank you

import datetime

def gettime():
return datetime.datetime.now()

print("CUSTOMER RATION BORROWING MANAGEMENT")
print("what do you want?\n 1. Log \n2.Retrieve")
d = int(input())

if (d==1):
name = (input("Enter customer name\n----"))
while (True):
grocerry = str(input("items\n----"))
price = (input("enter price\n----"))
a = str(input("Want to add more items?\ny for Yes -- n for No\n"))
if (a=="y"):
continue
else:
break

with open (f"{name}.txt","a",) as name:
name.write (str([str(gettime())])+" :- "+grocerry+":- "+str(price)+"\n")
print("Noted successfully.....")

else:
name = str(input("Enter customer name\n"))
with open (f"{name}.txt") as name:
for i in name:
print(i,end="")

Answer 1

In your snippet of code here:

if (d==1):
name = (input("Enter customer name\n----"))
namefile = open("{}.txt".format(name), "a") # Open the file first
while (True):
grocerry = str(input("items\n----"))
price = (input("enter price\n----"))
namefile.write(str([str(gettime())])+" :- "+grocerry+":- "+str(price)+"\n") # After adding each item, you want to write it into the file

a = str(input("Want to add more items?\ny for Yes -- n for No\n"))
if (a=="y"):
continue
else:
break

You can get rid of this section:

with open (f"{name}.txt","a",) as name:
name.write (str([str(gettime())])+" :- "+grocerry+":- "+str(price)+"\n")

And finally, when you reopen the file for retrieval:

name = str(input("Enter customer name\n"))
with open (f"{name}.txt") as name:
for i in name.readlines(): # This will allow you to read all the lines
print(i,end="")

Answer 2

thank you John