What should be instead of ”?” ?

Question

This code searches through lists and sees which values the two lists have in common, what i want to be printed is the number of those common values, for example if they have 2 numbers in common[3,7] then ”2” should be printed out.
https://code.sololearn.com/cTq8jia6labi/?ref=app

Answer 1

Lenoname

Either print i or x.

If you want number of common elements then increase counter.

count = 0

for i in a :
for x in g1:
if x == i:
count += 1

print (count)

-------
You can also store common data in new list like this:

newList = []

for i in a :
for x in g1:
if x == i :
newList.append(i)

print (newList)
print (len(newList))

--------
If you don't want loop you can also use set:

a = [6,7,3]
b = [5,4,3,1,7]

setA = set(a)
setB = set(b)

setC = setA & setB

print (setC)
print (len(setC))

Answer 2

Lenoname

You can check if count > 0: print count else print 0 point

Answer 3

Lenoname

Yes you can have but no need of elif. You can just do this without elif:

if x != i :
continue
count+=1

Answer 4

Lenoname

continue is use to skip the current iteration so if you don't write elif then that is also fine.

Answer 5

A͢J Thanks!!!it worked!! i dont know if the indentations are right though.
a = [6,9,8]
g1 = [5,4,3,1,7]
count = 0
for i in a :
for x in g1:
if x == i :
count+=1
if count > 0:
print(count)
else:
print("0 point")

Answer 6

If you want to use list. Then there is an easy way

a= [6,9,8]
g1 = [5,4,3,1,7]
count = 0

For i in a:
if i in g1:
count += 1

print(count)

Answer 7

A͢J can i have the
if x!=i: continue
Included?

Answer 8

A͢J lets say the programme didnt find any common values and ”0 points” should be printed, this wouldnt work:

a = [6,7,3]
g1 = [5,4,3,1,7]
count = 0
for i in a :
for x in g1:
if x == i :
count+=1
print(count)
else:
print("0 point")