why not printing address?

Question

//basic pointer
#include<iostream>
using namespace std;
main()
{
char a='a';
char *p;
p=&a;
cout<<p<<endl;
}

it printing garbage value.

Answer 1

The reason is due to the way that cout overloaded the << operator to handle char* pointers. It assumes that you wish to print the string that it points to, rather than the pointer.

A quick fix is to cast it to another pointer type that is not re-interpreted:
cout<<(void*)p<<endl;

More ideas are found here:
https://stackoverflow.com/questions/17813423/cout-with-char-argument-prints-string-not-pointer-value

*** BTW, main() should be int main() and it should return a value.

Answer 2

https://code.sololearn.com/cpztT5xWYgD7/?ref=app

Answer 3

cout<<&p<<endl;