Why it Outputs 8

Question

fib = {1: 1, 2: 1, 3: 2, 4: 3}
print(fib.get(4, 0) + fib.get(7, 5)

Answer 1

DAVID MPHANDE

fib.get(4,0) is looking to call fib[4] which already has the value 3 assigned to it, so ignores the attached value in your call.

fib.get(7,5) is looking to call a key: value that does not yet exist in your fib dictionary, so it assigns that key: value to the dict

3 + 5 = 8

#Why it Outputs 8

fib = {1: 1, 2: 1, 3: 2, 4: 3}
print(fib.get(4, 0) + fib.get(7, 5))

print(fib[4])
print(fib[7])

Answer 2

The output is 8 because from the in print it's written that -
fib.get(4,0) # This gives you the value of 4 in the dictionary which is 3 and did not give 0 because 4 is there in the dictionary.
fib.get(7,5) # This gives you the value of 7 but the key 7 is not there in the dictionary so it gives the value 5 which has been given in the second parameter.

So the output is 3+5 = 8.

Answer 3

Ooh 😮 i now get it, Thanks 👍