Find no of vowels in string?

Question

Why my output is coming 0?

#include<stdio.h>
#include<string.h>
int countvowels(char str[]);
int main()
{
    char str[]="helloworld";
    printf("vowels are %d",countvowels(str));
    return 0;
}
int countvowels(char str[])
{
    int count = 0;
    for (int i = 0;i !='\0';i++)
    {
        if (str[i] =='a' || str[i] =='e' || str[i] =='i' || str[i] =='u' || str[i] =='o' )
        {
            count++;
        }
    }
       return count;
}

Answer 1

Check the condition inside for loop

it should be

str[i] != '\0'

instead of i != '\0'

your code is also showing error stray 302
which means it has some extra hidden characters. these stray characters are causing errors.

don't copy codes from external resources

Answer 2

Thank you very much for helping me 😊

Answer 3

You are using loop condition i !='\0' which is Initially true, so loop not starting.. Actually you need str[i] != '\0'.

Your code have invalid characters, remove all.
may you copied it net source. Hope it helps.

Answer 4

302 error is coming bcz I copied it from my pc compiler and paste it to Mobile compiler.

Answer 5

Remove all those spaces where it pointing invalid characters. Or rewrite same code. Then it works fine ...

Answer 6

Ok👍