what does this code do?

Question

https://code.sololearn.com/c4ot0sKPOC00

it's the code for function that returns false if both of inputs are even or odd, otherwise it returns true. but , I didn't understand how does it works?
can someone explain it to me?

Answer 1

! ! ( ( Ͼ & 1) ^ (1 & Ͽ ) )

The function uses bitwise & (and) to examine the lowest bit, which is a determinant whether a number is odd or even. (1 indicates odd; 0, even).

It performs exclusive or ^ to determine whether they are different. Exclusive or is equivalent to the logical comparison operator !=. (True means not equal; False, equal)

The ! ! (not not) operators are used to convert the binary result of ^ into a Boolean True/False. The first ! converts the result into Boolean type, but undesirably negates the value. The second ! negates the value again to restore the original meaning.

You would get the same result with

( Ͼ & 1) != (1 & Ͽ )

But it wouldn't be as picturesque.

Answer 2

Its nothing more than comparison of two numbers