You want to take a list of numbers and find the sum of all of the even numbers in the list. Ignore any odd numbers.

Question

Please help me to solve this with python.

Answer 1

num = [ 1, 2, 3, 4]
for x in num:
if x % 2 == 0:
print(x+0)

Answer 2

Your solution?

Answer 3

Use for loop:
Here is my solution:

List = [ list of numbers]
sums = 0
for i in List:
if i % 2 == 0 :
sums += i
print(sums)

Answer 4

It's not working.. invalid syntax.expected output is 278

Answer 5

Kalyani Khakal
I guess the problem is with Print function. Make sure that all the words in print() are lowercase. I forgot to fix it when i was writing.

Answer 6

Ok

Answer 7

It still not working,I think the problem is in 1st line

Answer 8

Can i see your code?

Answer 9

List = [1,2,3,4,5,6,7,8,9]
sums = 0
for i in List:
if i % 2 == 0 :
sums += i
print(sums)

Answer 10

This code is working fine. I don’t know what is the problem.
Here you can test it yourself:

https://code.sololearn.com/cw7poVLUtep3/?ref=app

Answer 11

Thank u for your help..

Answer 12

No problem mate. :D

Answer 13

Java

Answer 14

You can use another list for storing even numbers within a loop the put that new list in the sum() function

Answer 15

Community organization and would

Answer 16

Use this code:
l= []
for i in list_numbers:
if i%2==0:
l.append(i)
else:
pass
print(sum(l))

Answer 17

Please help me to go further in my lessons in solo my heart finished and i can do anything just discussing

Answer 18

Better use numpy and sort and filter them then just simple addition will suffice

Answer 19

Why to suffer, try this:

a = list(range(26))
print(sum(filter(lambda x: x%2==0,a)))

Answer 20

Code:
1. nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
2. sum = 0

3. for num in nums:
4. if(num%2==0):
5. sum = sum + num

6. print(sum)

Explanation:
1. Initializes a list of numbers from 1 to 10
2. Initializes the value of sum to 0
3 & 4. Checks whether any value in the list is even
5. Adds these values together and stores them in the sum variable
6. Finally prints the sum