I have written a code. I want to make it look clean, please help.

Question

def wsd(n):
k = [int(x) for x in str(n)]
p = []
for i in range(0,len(k)):
p.append(k[i]*(i+1))
return sum(p)

k = [wsd(x) for x in input().split()]
print(*k)

Answer 1

Paul

I have written the same code!!
The code takes an integer

It multiplies every index of the given number to a real number(1,2,3....) Respectively and then output the sum of digits of the result.

Example:-
Input
15

Output
11

here 11 is the answer as wsd of 15 =1*1 + 5*2 = 11

Similarly,
70 = 7*1 + 0*2 = 7

Hopefully, you understood the problem. thank You

Answer 2

Another version, don't know if it is better, but i thought i could use yield:

def wsd(n):
for y in n:
p = 0
for i in range(len(y)):
p += (int(y[i])*(i + 1))
yield p

k = wsd([x for x in input().split()])
print(*k)

Answer 3

This code looks in my opinion clean. You want to make it no clean and shorter?

Answer 4

JaScript

I have edited the code now, earlier it had some repeated statements now I have deleted all of them.

Thanks for your Opinion.

Answer 5

It is easier if i know what your code is supposed to do, but i tried to make it simpler
def wsd(n):
k = [int(x) for x in str(n)]

p = 0
for i in range(len(k)):
p += (k[i]*(i + 1))
return p

k = [wsd(x) for x in input().split()]
print(*k)

Answer 6

# so in your opinion us this two(one)-liner a cleaner solution:
# my opinion: nah

a = list(map(int,iter(input('~> '))))
print(sum([i*-~a.index(i)for i in a]))

Answer 7

It looks correct to me .by the way nice work

Answer 8

Código para resolver

Answer 9

James Benita Thank You

Answer 10

Anshuman Routray
would this work? crazy mix of python functions, no list.

def wsd(n):
return sum(i*v for i,v in enumerate(map(int, [j for j in n]), 1))

k = [wsd(x) for x in input().split()]
print(*k)