Please what's wrong with this code

Question

word = input().lower()
if "1" in word:
print(word.replace("1", "one"))
elif "0" in word:
print(word.replace("0", "zero"))
elif "2" in word:
print(word.replace("2", "two"))
elif "3" in word:
print(word.replace("3", "three"))
elif "4" in word:
print(word.replace("4", "four"))
elif "5" in word:
print(word.replace("5", "five"))
elif "6" in word:
print(word.replace("6", "six"))
elif "7" in word:
print(word.replace("7", "seven"))
elif "8" in word:
print(word.replace("8", "eight"))
elif "9" in word:
print(word.replace("9", "nine"))
elif "10" in word:
print(word.replace("10", "ten"))

Answer 1

What is the aim of your code?

Answer 2

once try by doing this,
word=word.replace("1","one")
print(word)

Answer 3

Solved Problem
This is correct program

num = ['zero','one','two','three','four','five','six','seven','eight','nine']

def number2(n):
# If all the digits are encountered return blank string
if(n==0):
return ""
else:
# compute spelling for the last digit
small_ans = num[n%10]

# keep computing for the previous digits and add the spelling for the last digit
ans = number2(int(n/10)) + small_ans + " "
# Return the final answer
return ans

print("( Number To Word Converted )")
n = int(input("Enter Number: "))
print("Converted to word: ",end="")
print(number2(n))

Answer 4

Thanks a lot you guys

Answer 5

In supposed to turn any numeral ranging from 0 -10 in a string to words

Answer 6

First write case 10 before 1 and 0 otherwise its output onezero for 10

edit:
FrankE and only print one time at last....
you need all if there.. not elif, by this approach....

in fact, no need of if-else block checks.. you can directly write
word.replace (...).word.replace(..)... in sequence also..

Answer 7

oh god elif

Answer 8

Put the zero statement on top and at the last use else for ten