Why does the code iterate through odd numbers only?

Question

a = [1, 2, 3, 4, 5, 6, 7, 8]
for i in a:
print(i)
a.remove(i)
print(a)

Output:
1
3
5
7

[2, 4, 6, 8]

Answer 1

Kilian Andrew
a.remove(i) will remove i so then list size also get decreased.
Iterator points to next index so
Before removing an item say 1 is 0th index and 2 is in 1st index position but after removing 1, 2 goes to 0th index position.. And 1st index position value now is 3 which is value at next index to be printed.. This getting repeating till end..
Hope it helps..

Answer 2

Kilian Andrew Seriously??? So you didn't check your question?

As the name says, remove() removes the item. Print the list on each iteration to see what's going on.

Answer 3

Lisa I had omitted the remove function. So would you explain to me? It's followed by a.remove(i)

Answer 4

Is your question is
Why does..,? Or how does...?

Answer 5

Try using

a = [1, 2, 3]

for x in a:
print(x)

Output:
1
2
3

Answer 6

Did you check it in playground..?
What is your output?

it prints all numbers...

Answer 7

It prints all items.

Answer 8

Output:
1
3
5
7
Jayakrishna🇮🇳 Lisa

Answer 9

No:
https://code.sololearn.com/c1Ss2iO6cfDQ/?ref=app

Answer 10

Jayakrishna🇮🇳 I had omitted the a.remove(i)

Answer 11

Thanks Jayakrishna🇮🇳

Answer 12

Lisa I get it now.