Sum of the series

Question

Write a program to find the sum "S" of the series where S=x-x**3+x**5+..... upto "N" terms.

INPUT:
The first line of input is an integer "x".
The second line of input is an integer N.

Explanation:
If we take "x" value as '2' in the series upto '5' terms.
Then the series is 2 - 2**3 + 2**5 - 2**7 + 2**9
So, the output should be "410".

Sample Input 1:
2
5
sample Output 1:
410

Sample input 2:
3
2
Sample Output 2:
-24

Write the python code in Answer Box.

my code.
S=int(input())
N=int(input())
j= S**3
for i in range(0,N):
if i%2 == 0:
j = j + i
else:
k = k - i
print(j+k)

Answer 1

Vijay Satya Srinivas

s = int(input())
n = int(input())

result = 0

for i in range(1,n+1):
if i%2:
result += s**(i*2-1)
else:
result -= s**(i*2-1)

print(result)

'''You want N iterations, each iteration is to generate an odd number.

So create your loop as
range(1, n+1).
if n = 5, then range will be 1,6 which will produce 1,2,3,4,5

1*2-1 = 1
2*2-1 = 3
3*2-1 = 5
4*2-1 = 7
5*2-1 = 9

We have now created a formula which can generate your required exponent, but now we need to determine when to += the result or -= the result.

Determine if your iteration is odd or even, then apply the appropriate formula by using iteration%2'''

Answer 2

If you need help with your code, please LINK your code.

If you think other would do your homework for you: No.

Answer 3

Vijay Satya Srinivas
This looks like an interesting challenge / concept, but it also looks like your homework.

Please show your attempt so we may assist.

Answer 4

Look at the formula again:
On each iteration of the loop you need to raise x by the power of the next number that is in the 3, 5, 7, ... series. Then you add or subtract this number from your sum. You do this N times

Answer 5

where k is not defined