Izzy the Iguana Code Question Need help with my answer

Question

Practice Problem:

Your pet Iguana has run away, and you found it up in a tree! It will come down right away if you brought the right snacks, but if you don't have enough, you will have to wait. You need 10 total snack points to bring it down. Lettuce is worth 5, Carrot is worth 4, Mango is worth 9, and Cheeseburger is worth 0.

ANSWER ATTEMPT:

#FOOD PRICES
Lettuce = 5
Carrot = 4
Mango = 9
Cheeseburger = 0
############

foods = input()

def foods_list_convert(x):
a = list(x.split(" "))
return a

foodList = foods_list_convert(foods)

i = 0
while i < len(foodList):
grub = 0
if foodList[i] == str(Lettuce):
grub += Lettuce
elif foodList[i] == str(Carrot):
grub += Carrot
elif foodList[i] == str(Mango):
grub += Mango
elif foodList[i] == str(Cheeseburger):
grub += Cheeseburger
i += 1

if grub > 10:
print("Come on Down")
else:
print("Time to wait")

-------------------
MY THOUGHTS:

I think issue with the variable grub. Don't know how to take the info out of the while loop and use the new grub that's totaled up.

Answer 1

Why not simplify with dictionary?

snacks = {"Mango": 9, "Lettuce": 5, "Carrot": 4}
points = 0
inv = input().split()

for x in inv:
points += int(snacks.get(x, 0))
if points >= 10:
print("Come on Down!")
else:
print("Time to wait")

Answer 2

str(Lettuce) : what you do mean by here? It returns str(5) => "5"
just use "Lettuce". same for next all.

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Answer 3

Was able to fix with this:

#FOOD PRICES
Lettuce = 5
Carrot = 4
Mango = 9
Cheeseburger = 0
############

grub = 0

foods = input()

def foods_list_convert(x):
a = list(x.split(" "))
return a

foodList = foods_list_convert(foods)

i = 0
while i < len(foodList):
if foodList[i] == "Lettuce":
grub += Lettuce
elif foodList[i] == "Carrot":
grub += Carrot
elif foodList[i] == str(Mango):
grub += Mango
elif foodList[i] == str(Cheeseburger):
grub += Cheeseburger
i += 1

if grub > 10:
print("Come on Down")
else:
print("Time to wait”)

----------------

I defined the var grub, outside of the while loop.

Then changed as an example:
str(Lettuce)

to

"Lettuce"

Answer 4

What about Mango, Cheeseburger? Do the same for those.
use if grub >= 10 : >= instead of >