Isogram detector : simplify my code

Question

word = input()
dict ={}
for x in word:
if x not in dict:
dict[x]=1
else:
dict[x]+=1

final=list(dict.values())
if max(final)==1:
print("true")
else:
print("false")

Hello, I need help to simplify the end of my code. I had to convert my dictionary to a list to use the max() command. Would you find an easier way to make it works ?
(Isogram detector challenge, it has to output true is the word dosent contains 2 time the same letter and false if a word contains 2 times the same letter.
Word = true
Carrot = false)

Thank you :)

Answer 1

Max Lang ,

you can use max() also for dictionaries:

...
if max(dict.values()) == 1:
print("true")
else:
print("false")

allow me some hints for general improofment:

- please use proper indentation of 4 spaces per indentation level

- do not use names of objects / classes like 'dict' as a variable name, because this can cause issues

Answer 2

Remember that a set holds only unique values. You could build a set from all the letters in the original word, then compare the set's length with the original word length.

word = input()
s = set(i for i in word)
print(len(s)==len(word))

Answer 3

Max Lang ,

see the code how it should be indented:
https://code.sololearn.com/cXG86pIKhyMr/?ref=app

Answer 4

Thank you very much both of you for your answers, it amaze me to see its always so easy 🤣😅.
Can you explain me what you mean by using proper indentation of 4 spaces ? Thank you !