Is this code safe?

Question

#include <stdio.h>

int main(void) {

char input[10];
scanf("%s", input),

return 0;
}

Answer 1

yes it is safe but replace comma with semicolon at the end of scanf

Answer 2

To be safer, you can specify a limit for number of characters to be read within the conversion specifier.

Specify a value of <buffer-size - 1>. So in this case your buffer <input> size is 10 characters. Thus you specify 9 for the limit of characters to be read in.

scanf( "%9s", input );

Why bother setting the read buffer limit? because something can go wrong if a program attempts to write more than what it was allowed for, or supposed to.

More about scanf() function
http://www.cplusplus.com/reference/cstdio/scanf/

Answer 3

in addition this code will read a single word from user so if u add spaces after words, the program will only read the first word