why does result is 5?

Question

https://code.sololearn.com/WQMySOA2q1VN/?ref=app

Answer 1

First loop makes i=4
I=I+1=>i=1, and next i++; so I=2
I=I+1=>i=3, and next i++; so I=4
4<3 false, loop stops..

if block i%2==0 cause i++; so i=5 now

If provide your understandings then it helps you correct your answer, if any wrong..
Hope it helps..

Answer 2

In the last iteration
i= 3 , then i++ = 4 according to (i =0, i<3, i++)

Then it moves to the conditions
if i%2 ==0 , which is true then it increment by 1

Making it 5

I hope this helps

Answer 3

This is the order of execution :
i=0;
i<3

i=i+1

i++;
i < 3

i=i+1

i++;
i<3

..
..

there checks are
0<3 true initial
2<3 true, after 1st iteration
4<3 false, after 2nd iteration

Answer 4

But when i=3, this loop will stops.
I = 3, it's <3, so i =2