Why I am getting an error? What is the purpose of return here?

Question

return is supposed to return a value from the function that can be used in the whole program right?
Why is it not working?
https://code.sololearn.com/cbts65Vuvq1j/?ref=app

Answer 1

Logics Suker no, "return" stops the function and outputs the value to be assigned to the variable, as shown in the first example.☺️

Answer 2

Logics Suker ,

this may claryfy the use of return and the output from outside the function:
(we don't need to use *global* variable when the code is done properly)

def haha(x):
# a = x # we don't need this
#print(x*x) # option: print this expression from inside the function
return x * x # e.g. return this expression

res = haha(9) # we can accept the returned value from the function by storing it in variable like *res*.
# it can be used for any purpose in main part of the program
print(res) # last step is to output, or do with it whatever is needed ...

Answer 3

"a" is a local variable, that is, it is defined inside the function and cannot be used outside of it. So you are trying to print another variable "а" that you haven't defined yet.

#1:
def haha(x):
a = x
print(x*x)
return a

a = haha(9)
print(a)

#2:
a = 5
def haha(x):
global a
a = x
print(x*x)

haha(9)
print(a)

👇👍 😉

def squaring(x):
return x*x

print(squaring(9))

Answer 4

Solo what is the purpose of return statement then. Doesn't it returns anything that can be used in the whole program at any time?

Answer 5

JOKER I do want to print variable a that is returned by the function

Answer 6

def haha(x):
print(x*x)

haha(5)

Answer 7

def haha(x):
a = x

return a*a
print(haha(9))

#this

Answer 8

def haha(x):
print(x*x)
return x*x
haha(9)
print(haha)

Answer 9

Hello, your 'a' variable is inside the function scope and you re calling it on the global scope which will return an error since it is unknown to a global scope while declaring the 'a' to local/function scope.

Answer 10

https://code.sololearn.com/cfaIAd71im1z/?ref=app