Question related to lambda

Question

x='cyzxyz'
(lambda x : print(x))(x)
O.p - cyzxyz

Why there an x outside of print statement ? Could anyone explain the second line pls

Answer 1

x = 'cyzxyz'
(lambda x : print(x))(x)
^
parameter of the function

(lambda x : print(x))(x)
^
function "body", x refers to the parameter

(lambda x : print(x))(x)
^
argument that you pass to the function; x refers to the variable x, that holds the string

You could rewrite the code like this:
y = 'somestring'
(lambda x : print(x))(y)
or
def fun(x):
print(x)
fun(y)

Answer 2

Again we can rewrite the code to make it clearer:

a=[lambda x=num:x*10 for num in range(10)]
for fun in a:
print(fun())

Here num is the default value for the x parameter

Answer 3

Lisa Thanks u so much for ur explanation. And I have one more query

a=[lambda x=x:x*10 for x in range(10)]
for i in a:
print(i())

What does lambda x=x mean ? Could u explain in simple terms pls