if string[i] is equal to 0, why multiplies with (i+1)?

Question

string = input()

i = 0
while (i < len(string)):
print(string[i] * (i+1))
i += 1

Answer 1

It depends on what you want to output.
If string is cat, you will print:
c
aa
ttt

Answer 2

string[i] never equal to 0.

print( "Test this " * 3 )