How the inner function is executing in this scenario

Question

When I give return Inner statement, how the Inner function is executing ? I didn't give Inner(), I just gave Inner .

https://code.sololearn.com/ctcgHUr08B24/?ref=app

Answer 1

Levi

@decor is work like this if you don't write @decor on above the function

def decor(func):
def inner():
print('hello from inner')
return inner
#@decor
def display():
print('Hello')
#display()

r_print = decor(display)
r_print()

------------you can understand by this example------

def abc(func):
def Inner():
print('hello from inner')
return Inner

@abc
def display():
print('Hello')

display()

see I have changed function name here 'abc' and written @abc on above the function display() it means display() function internally call abc function and print statement of abc function

Answer 2

A͢J what is r_print()

Answer 3

A͢J I can understand ur answer,
But in
return Inner
How the Inner function is executing ?
It should be
return Inner() right !?

Answer 4

Levi

No in python function can be return as a variable so there is return Inner

Assigned returned function to a variable r_print but actually it is a function so there is r_print()

also we can pass function as an argument so there is decor(display)