Please any one of you please the below code to me

Question

def apply_twice(func, arg):
return func(func(arg))

def add_five(x):
return x + 5

print(apply_twice(add_five, 5))

Output is 15

Answer 1

let me try to break it down for you.

1. the apply_twice function has two arguments. The first Argument will hold another function. then the second function will hold the number.
2. The return statement in the apply_twice function will call the add_five function twice and pass in a given argument which is a number.

3. The add_five function is defined and it returns the mathematical operation
4. In The print statement it will output the result.
In The print statement the apply_twice function is called with the add_five function and a number.

in the return statement of the apply_twice function. add_five function is called twice.

let me give how the return statement will work

return func(arg)
# it will be 5+5 => 10
return func(func(arg))
#it will be 10+5 => 15

Answer 2

MATOVU CALEB
Nicely explained
😁👍

Answer 3

Hi! do you not understand how the result was 15?

Answer 4

add_five() wrapped into apply_twice() unrolls into:
add_five(add_five(5))

because it follows the pattern:
func(func(arg))

func is add_five
arg is 5

Answer 5

Yeah I didn't understand, how the output is 15, would you please explain me