The default case must appear at the end of the switch. It's wrong

Question

i am new .but i think it's wrong in the feed.

Answer 1

default case works when all the cases won't work. Hence, it must be placed at last

Answer 2

If you place the default case first then it will only evaluate that. Example's Below.

int age = 30;

switch(age)
{
default:
cout << "You not 30?" << endl;
break;

case 30:
cout << "You are 30...." << endl;
break;
}

In the above example the first thing to be processed is the default statement and that result in the case 30 statement not to become evaluated.

//try now at the end

int age = 30;

switch(age)
{
case 30:
cout << "You are 30...." << endl;
break;

default:
cout << "You are not 30?" << endl;
break;
}

In the above example the case 30 statement is processed first this means that the switch has a chance to processes the age variable being 30. In the first example it does not have a chance to process the case 30 statement because default means nothing above me in the switch statement was true, therefore process the code under me.

Answer 3

No Zhang, You are wrong

Answer 4

it is also work when default in the middle of switch .
https://code.sololearn.com/cLA4KIn97gdv/?ref=app

Answer 5

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