Can anybody explain what's bug in my code!!

Question

Everything is good in my code but it's generates some errors with my expected output and i wanted to remove all bugs!!
https://code.sololearn.com/czHP8g11jPsZ/?ref=app

Answer 1

Jayakrishna🇮🇳
we need to writing only a function and rest of the work leetcode doing itself. no format required by yourself, you've to return a array only.

Answer 2

SoloProg
I was looking for c program, well thanks for c++ codes ☺️

Answer 3

#include<stdio.h>
void runningSum(int*ar,int n,int*r){ //void
for(int i=1;i<n;i++)
*(ar+i)+=ar[i-1];
//r = sizeof(ar)/sizeof(ar[0]); // no need

//return ar; // no need as you not saving it..
}
int main(){
int ar[] = {3,6,9,8,5};
int n = sizeof(ar)/sizeof(ar[0]);
int p;
runningSum(ar,n,&p); // arrays are by default pass by reference
for(int i=0;i<n;i++)
printf("%d ",ar[i]);
return 0;
}

Answer 4

Jayakrishna🇮🇳 can you please solve leetcode 1480 problem..
https://leetcode.com/problems/running-sum-of-1d-array/description/

That's my question the runningSum function should return any address or address block!

Answer 5

So share the code given.
To understand problem , Next separately mention your tried function..

Answer 6

class Solution {
public:
vector<int> runningSum(vector<int>& nums) {
int s=0;
for (size_t i=0; i<nums.size(); i++) {
s += nums[i];
nums[i] = s;
}
return nums;
}
};

Answer 7

Jayakrishna🇮🇳
I resolved the problem, you can see my codes attached to my question.

Answer 8

Rajeev Sharma
So it asked to use malloc..
Got it. Well done.

Answer 9

Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

I need to sign up to see problem..
But just looking at description, I think it will give input or manual array data..
Is it asking full code to write? Or just a part of code? How you need to print? Space separated.. Or any other farmat?