Fill in the blanks to select all images of the page and change their src attribute.

Question

var arr=document.
getElementsBayTagName("img");
for(var x=0; x<arr...........; x++) {
arr[x]src="demo.jpg")
}

Answer 1

var arr=document.getElementsByTagName("img");
for(var x=0; x<arr.length; x++) {
arr[x].src="demo.jpg";
}

Answer 2

var arr = document.
getElementsByTagName("img");
for(var x=0; x<arr.length; x++) {
arr[x].src = "demo.jpg";
}

Answer 3

answer

attr
#img
src

Answer 4

Fill in the blanks to set the alt attribute of the image with id="img", and alert the value of its src attribute....

$("#img")........("alt", "Demo");
alert($("...........").attr("............."));

Answer will be : attr, #img, src

Answer 5

don't answer follow my order's i am 109 years old

Answer 6

var arr=document.getElementsByTagName("img");
for(var x=0; x<arr.length; x++) {
arr[x].src="demo.jpg";
}

Answer 7

creat
thank you🙋

Answer 8

var arr = document.
getElementsByTagName("

img

");
for(var x=0; x<arr.

length

; x++) {
arr[x].

src

= "demo.jpg";
}

Answer 9

thanks

Answer 10

Answer is wrong why

Answer 11

span
for
x

Answer 12

par
removingchild
node

Answer 13

length and src

Answer 14

img
length
src

Answer 15

var arr = document.

getElementsByTagName("
img
");

for(var x=0; x<arr.
length
; x++) {

arr[x].
src
= "demo.jpg";

}

Answer 16

attr, #img, src

Answer 17

var arr = document.

getElementsByTagName("
img
");

for(var x=0; x<arr.
length
; x++) {

arr[x].
src
= "demo.jpg";

}

Answer 18

$("#img")........("alt", "Demo");
alert($("...........").attr("............."));

Answer will be : attr, #img, src