Return true with palindromes

Question

Trying to return true is number is palindrome in c++:
bool isPalindrome(int x) {
//complete the function
//convert to string
string stringOfX = to_string(x);
char* array = new char [stringOfX.length() +1];
array[stringOfX.length]= "/0";
// add each char of stringOfX to array
for (i =0; i< stringOfX.length(); i++){
array[i]= stringOfX[i];
}
if(array[i] == strrev(array[i])){
return true;
} else {
return false;
}

Answer 1

First you can save your code on SL playground and code step by step, test and see how it works, similar to this example:

https://code.sololearn.com/ccf1IOVoECrX/?ref=app

Answer 2

array[stringOfX.length() ] = '\0'; // is the correct way. You are missing () and use single quotes for characters. And use back slash \ , not /.
Loop variable i is not declared. Declare it as int i=0 or size_t i = 0;

For reverss comparision of enter string, there is no need subscript [i] so remove it.
( array == strrev(array) )

But strrev() is non-standard function of cstring of windows os supported. So may not work in all compilers. [ And not work in SL compiler].