Why this program not show output ??(for armstrong number from 1 to 100)

Question

https://code.sololearn.com/clVzfcKEs9Xu/?ref=app

Answer 1

#include <stdio.h>

int main() {
int i, n, num, d;

for (i = 1; i <= 100; i++) {
n = i;
num = 0;
while (n != 0) {
d = n % 10;
n = n / 10;
num = num + (d * d * d);
}
if (i == num)
printf("%d\n", i);
}
return 0;
}

your Programe having some indentation mistake

Answer 2

How

Answer 3

1 should've to print

Answer 4

I got it thanks 🙏🏻

Answer 5

Vaibhav thanks 🙏🏻

Answer 6

Because i is never equal to num in your code on line 15

Answer 7

Add the following line before line 15 and check output:

printf("i = %d, num = %d", i, num);

Answer 8

hmmm...idk,why is it doing that?