Why this happened?

Question

print(-10**2) » output is -100

n=-10
print(n**2) » output is 100.

Answer 1

Lisa is spot on with her answer

The first example -> print(-10**2)
is interpreted as
- ( 10**2) -> -100

The 2nd example ->
n=-10
print(n**2)
is interpreted as

(-10)**2 -> 100

n = -10 is applied before the exponentation

Answer 2

"**" has higher precedence than "-", so "**" is considered first.

Answer 3

Wow bro, it's really confusing how this happens!

Answer 4

Yabtsega Alem Create an own thread for your question, do not hijack other people's thread

Answer 5

ⵢⴷⵢⴷ
Review your understanding of mathematical operator precedence.

This is a math problem, not a code problem

Answer 6

ⵢⴷⵢⴷ
I am sure that you recognise that 10 is different to -10

n is a variable which has a value of -10

This value is then passed to the equation **2
-10 * -10 = 100

The equation of -10**2 is subject to operator precedence.

** has a higher precedence than -

so the equation operates on
10 * 10 = 100

Then it uses the - to make
-100

Answer 7

Thanks you Wittkopp but I will need more time to understanding it more.

Answer 8

Yeah, 😅 that's a bad news for me because I'm not good in Math.

Answer 9

Ashly Mathew
Create your own thread for asking your question. Do not hijack other people's thread.

Answer 10

Python uses () around operators not variabels.

Answer 11

The math rules are that, - * - = +

Example: -4 * -6 = 24, so -10 * -10 = 100

That's what I learned at school.

Answer 12

print(-10**2)>>>> this is like this firstly it will Calculate the (10**2) and then that small negative sign will be added to the number

So
in your next Part
its like this : n=-10
print(n**2)

>>>>>>>>> print( (n)**10) >>> print((-10)**2) so the output will be 100

Answer 13

Why the same values with the same operation result in different outcome?
Is there difference between an assigned negative value and a non-assigned negative value ?

Answer 14

i am pretty sure it is Python.

Answer 15

It is because python automaticly sets () around **