When a break breaks?

Question

i=5
while True:
print(i)
i=i-1
if i<=2:
break

Why it doesn't print 2 even if it's before the break in the code?

Answer 1

Dario Zaccheroni
because the break statement is executed when 'i' is less than or equal to 2`if i<=2`
If you want to print 2 before breaking out of the loop,
change the statement `i==2` insted of`if i<=2`.

Answer 2

Dario Zaccheroni

Your mistake is little bit, that you use '=' sign if you remove '=' sign in if block then counting print like this:

5
4
3
2

Answer 3

Since are subtracting before the check where you break, it is not printing it.

So when i=3,
1. The prints "i" which is 3
2. Subtracts 1 from "i" that is currently 3 and gives you 2 and assigns "i" to 2
3. Checks if "i" is equal to or less then 2.
4. That check results in True which means the program breaks.

Answer 4

The code you've provided prints numbers starting from 5 and decreasing by 1 in each iteration of the `while` loop. However, it stops when `i` becomes less than or equal to 2 due to the `if i<=2` condition and the `break` statement.

In the last iteration, when `i` is equal to 2, the loop prints 2 as expected, and then the `if i<=2` condition is checked. Since 2 is indeed less than or equal to 2, the `break` statement is executed, which immediately exits the loop before another iteration can take place.

So, in this case, the code behaves correctly and stops before printing 1 because the `break` statement interrupts the loop once the condition is met.