Hello guys is there a problem in this Python code of mine. it gives the expected out put but still i cant get the marks.

Question

players = ["Alice" , "Bob" , "Charlie" , "David ", "Eve" , "Frank"]

#Create 3 lists with 2 players each
#Use slicing to create a list for Group 1
g1 = players[0:2]

#Use slicing to create a list for Group 2
g2 = players[2:4]

#Use slicing to create a list for Group 3
g3 = players[4:6]

print("Group 1:\n",g1)
#display the 1st group

print("Group 2:\n",g2)
#display the 2nd group

print("Group 3:\n",g3)
#display the 3rd group

Answer 1

John ,

here are some hints how we can achieve the expected output in one line of code:

the reason for this single space at the beginning of the second line: when using comma separated arguments in print() function, python is inserting a space by default.

> to avoid this, we can use:
this is overwriting the default value for the separator by an empty string.
print("Group 1:\n", g1, sep='')

> second option is to use f-string instead:
print(f'Group 1:\n{g1}')

Answer 2

I also got the same problem initially!
Print g1, g2, g3 in different lines means use another print function to output g1 and same for g2 and g3.

Answer 3

You code produces an extra space before each list, not exactly matching the expected output.

Answer 4

thanks koli it worked