Java System.out.println output

Question

System.out.println((1+"1")+1+1)
Why output of this statement is 1111

Answer 1

Because there is a string before the integer value

(11) + 1 + 1; here 11 inside braces is a string
1111

braces has higher preference so since there is no braces before 3rd 1 so that would be go with 11 which is string

If you add braces before 1 + 1 then output will be 112

System.out.println((1+"1")+(1+1));