"Please help me correct this code."

Question

Note: When finding the sum of the digits until only one digit remains, only integer operations are allowed (no string or list operations).

Example Input/Output:

Input:
23
Output:
5

Explanation: The sum of the digits of 23 is 2 + 3 = 5, which is a single digit.

Input:
24682
Output:
4

Explanation: The sum of the digits of 24682 is 2 + 4 + 6 + 8 + 2 = 22. The sum of the digits of 22 is 2 + 2 = 4, which is a single digit.

Answer 1

When writing a number you want to add to another number, add a float(x), with x being the number.
For example: 1 + 3. When i want it to print out 4, not 13, i write print(float(1) + float(3)). This must print out a 4.0 . Hope this helps!

Answer 2

def add_(x,s):
if len(x)!=1:
s=sum(x)
x=[]
for i in str(s):
x.append(int(i))
return add_(x,s)
else:
return print(s)
a=int(input("Enter any Integer No. : "))
print()
x=[int(i) for i in str(a)]
add_(x,0)

Answer 3

https://sololearn.com/compiler-playground/cTZzJB74oKFQ/?ref=app

Answer 4

Mohamed Beder Oumar ,

Nice idea. This fixes the errors. Somebody else can put the loop in a loop to keep doing passes until its a single digit.

num = abs(int(input()))
sum = 0
while(num):
sum += num % 10
num //= 10
print(sum)

Answer 5

ANKIT CHANDOK ,

Nice recursion. My tweaks:

def add_(x, s):
if len(x) != 1:
s = sum(x)
x = []
for i in str(s):
x.append(int(i))
return add_(x, s)
else:
return s

a = input("Enter a non-negative integer: ")
print(a)
x = [int(i) for i in a]
print(add_(x, 0))

https://sololearn.com/compiler-playground/cRtsxtvc3dQ7/?ref=app

Answer 6

https://sololearn.com/compiler-playground/cCu3WhjT5C1l/?ref=app

Answer 7

num = ?
sum=0
While(X):
sum += num%10
num //= 10
print(sum)

Answer 8

Hii