How to call overloaded operator from different overloaded operator

Question

Hi

I have overloaded < operator as well as > operator for a custom class.

I would like to remove one function definition and Instead call other one with negate effect.

For example

Call < overloaded operator and return reverse of result as output of > operator.
https://sololearn.com/compiler-playground/cE5smx6LGeKH/?ref=app

Answer 1

The link you have shared is broken and I cannot open it from Windows OS laptop.

Answer 2

I can check link in android app.

No, question is not same.

Here, I am ok with Two definition but in a different way

Something like below:

bool islessthan(int a,int b)
{
return a<b;
}

bool isgreateethan(int a,int b)
{
return !islessthan(a,b);
}

Basically, I need to call operator < from operator >

Answer 3

I understand your point of inequality and < with > but I need a mechanism if available to call one overloaded operator from another overloaded operator

Answer 4

is this a duplicate post?

https://www.sololearn.com/Discuss/3311030/?ref=app

Answer 5

maybe. But wouldn't your isgreaterthan be actually be >= ?

!(a<b) also includes a==b

it might or not matter, depending on your use case, like sorting, but > would be wrong if you were to use it for two equal values...

it would be better to use

bool isgreaterthan(int a, int b){
return islessthan(b, a);
}

Answer 6

relational operators can be constructed from at minimum of 2 operations. Since < is required by the stl, the other would be ==

define these:
a < b a less than b
a == b a equal to b

from those two we can derive:
b < a a greater than b a > b
!(a == b) a not equal to b a != b
!(a < b) a greater than or equal to b a >= b
!(b > a) a less than or equal to b a <= b

https://www.geeksforgeeks.org/relational-operator-overloading-in-cpp/