Why j have a 4 value?

Question

function count() {
var i, j; //
for (i = 0; i < 3; i++) {
j = i * 2;
}

alert( i ); // i=3
alert( j ); // j=4
}

Answer 1

that "for" loop work
in first time j = 0*2
in seond time j = 1*2
The last time (thirth) j = 2*2

At last "j = 4"

Answer 2

Yep so many people why i = 3
look at this
for(i=0;i<3;i++)
In second condition is false so loop is stop
but that loop execute i++ along too (in thirth time)
So i=3 at last

Answer 3

If you have a loop like this:

for (i=0;i<3;i+=0.4) {
/* do something if i<3 */
}
alert(i);

... the variable 'i' will have successively the values 0, 0.4, 0.8, 1.2, 1.6, 2, 2.4, 2.8, 3.2: at first value of not i<3 ( here 3.2 ) the loop break BEFORE executing its body instruction, so last value of 'i' really used by the loop instructions is 2.8 but last value assigned to it is 3.2 ;)

Answer 4

but I last value 3

Answer 5

but why I =3

Answer 6

when I =3 loop will be stop yes I understand right and totally have a 3 value loop always working so

Answer 7

thx guys very much I understand all