+ 2
can someone explain me something
my boy told me that if we put on a chess board' square a grain of rice then double it, at the end of the 64th square there is enough rice to feed few 1000's people. for fun we tried to code this as shown, i know it writes $rice every time but the result is correct but if i write the echo line after the while statement, i get one line but the answer is wrong $rice=1; $square=1; do{ echo "$rice <br/>"; $square++; $rice*=2; } while($square<=64);
6 Respostas
+ 7
In your while loop echo is before the multiplication, so after the last echo printed the variable $rise is doubled again.
If you move the echo outside the while you will print the double of the last echo printed in the while loop.
I hope this explain.
+ 6
Your code works for me:
https://code.sololearn.com/wYyQt2V6B20p/?ref=app
+ 5
If the echo is inside the loop, it gets called and executed with each iteration of the loop, assuming currently calculated variable $rice.
If it is outside the loop, it is called only after iterating and ultimately calculating the $rice variable.
+ 3
Yes, a do-while loop is first executed and only then the while condition is checked. Putting echo outside caused it to only be executed once. Right after the do-while loop ended.
+ 2
what is the output you need and what output do you get? you know the do-while first executes the statement and then the check? try a while or for loop instead
0
should have remembered that the loop is being excecuted before the condition is checked. Having $rice being printed after the do while loop caused $rice one time to many. is that correct?