Tell me output of this and explain.

Question

#include<stdio.h>
#define mac(x,y) x%y+x
void main(){
int i=4,j=2;
printf("%d\n",mac(i+j,3));
}

Answer 1

define doesnt work like a function. the preprocessor just replaces every "mac(...)" before compiling.

that means that i+j doesnt get calculated but every x is replaced by i+j

so when the program gets compiled, you print "i+j%3+i+j".
that would be "4+2%3 + 4+2" and thats 12

Answer 2

ok ,I got it.