Does the value of x=x-- evaluates as the original value of x or it increments by 1?

Question

there is ambiguity on the outcome.

Answer 1

It means:
if x=10;
now when
x=x--;
so put x original value into x(left hand side one)
-- is a post decrementer here meaning first use it or assign then decreament but as we have used the value which is 10 so -- has no significance.
If you did like this:
x=--x;
then you would get x equal to 9,in this case first subtract by 1 then use it or assign to left side x.

Answer 2

Let x here be 10 originally, then it will be easier to explain...

a=b-- will mean that b's original value shall be passed to a and b is to be decremented by 1. So if a=2 and b=1,
a=b-- makes b=0 and a=1.

Now, expressions in C++ are always executed from left to right. and if there is an assignment, the whole expression is simplified to the end and then assigned...

So when we try x=x--;

x becomes x--, and so will become 9 later...

But now, before it becomes 9, it is assigned to x.

So x remains to be 10.

Thus, printing x after this will give you 10 (assuming start at 10) no matter what.

Though if you try x=--x, this will give a 9.

Answer 3

@Retr0
-- is decrement, ++ is increment.

Answer 4

how will it increment with this sign -- (correct me if I am wrong I have forgot a little things about c++)