why this output 2 not 3 ? #include <iostream> using namespace std; int main() { int x=1; x=x++; cout<<++x; }

Answer 1

@Josyah: The second part is not really true.
Anyways the code is executed in the following order:
1. x is set to 1 (x=1)
2. the value of x is incremented to 2 (x++)
3. a temporary variable with the xs original value of 1 is returned (x++)
4. x is assigned the temporary variable that is 1 (x=)
5. x is incremented to 2 (++x)
6. the value of x is returned (++x)
7. the value is outputted (cout <<)

Answer 2

x = x++ is the same as just putting x++. And cout << ++x is printing x before it is iterated once more

Answer 3

Yes, your correct. I had them backwards not paying attention. Thanks for point that out, i dont use ++val that often

Answer 4

@Josyah: No prob, I rectified an ordering mistake that did not have any influence on the outcome and hopefully improved the formulation.

Answer 5

thanks Stefan