Fill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exc

Question

can you help me

Answer 1

You need to match two "any character", followed by an exclamation mark. In regular expressions, "any character" is matched by using a dot. And the exclamation mark is a regular character, so you match it using... an exclamation mark :)

So you are looking for:

..!

Answer 2

answer is
r"..!quot;

Answer 3

the answer is r

Answer 4

+

Answer 5

str = r "I am \r\a\w!"

Answer 6

ill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exclamation mark.

answer is
r"..!quot;

Answer 7

Fill in the blanks to replace all '!' characters in str with a dot '.'

Answer 8

Fill in the blanks to match strings that are not entirely composed of digits.

import re

pattern = r"[

^

0-9

]

"

m = re.search(pattern, "Hi there!")

Answer 9

ans is r

Answer 10

r use

Answer 11

Is this answer correct? I fill ! in the blanks but it show false.

Answer 12

Sounds difficult and is difficult, sorry

Answer 13

use +

Answer 14

Helpful

Answer 15

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

Answer 16

r"(42)+quot;

Answer 17

It's answer is r"..!quot;

Answer 18

answer
r"..!quot;

Answer 19

Fill in the blanks to match strings that are not entirely composed od digits

Answer 20

str = r "I am \r\a\w!"