Please explain how this works?

Question

int x=0;
for(int i=1 ; i<4; i++) {
x+=i;
}
cout << x << endl;
//output 6

Answer 1

Iteration 1 : i = 1; x += 1 => x = 0 + 1 = 1;
Iteration 2 : i = 2; x += 2 => x = 1 + 2 = 3;
Iteration 3 : i = 3; x += 3 => x = 3 + 3 = 6;
i becomes 4 and loop condition (i < 4) fails.

Answer 2

@Krishna thank u 😊

Answer 3

@Paavan. thank you. yeah. I got it 😊

Answer 4

first you have declared an integer variable x = 0.
then you have declared a for loop where the condition is that if i=1 then i<4.i++.
here the compiler will run this loop upto when the i is smaller then 4 , as soon as i becomes 4 then it's not smaller then 4, it's equal to 4, so the loop will break executing. Here the i++ means that only that upto the condition becomes false,
execute the loop continuously and everytime the loop will execute it will add 1 to x itself. and after the execution of loop gets completed then it will print the x.
i think you may have understood.

Answer 5

welcome☺👍