I don't know why am getting confused, can some shine more light to this part?

Question

<?php
$a = 10;
$b = $a++;
echo $a;
?>

/* echo $a, this part I thought it was supposed to output $a which is 10, why is it outputting "11"? */

/* I also thought that by calling $b the output will be " 11". */
and also what is the difference between a++; & ++a?

Answer 1

I hope this could help
<?php
$a1 = 10;
$b1 = $a1++;
/*output: $b2 = 10 and $a1 = 11
this will pre-increment,
get the value and increment $a1
*/

$a2 = 10;
$b2 = ++$a2;
/*output $b2 = 11; $a2 =11;
post-increment, this will
increment first and place the value
*/
?>

Answer 2

$a = 10; // defines variable a with value 10
$b = $a++; //defines variable, post increment var a.
echo $a; //output 11
++a uses pre increment operator and returns value after increment ( adding 1).
a++ uses post increment operator and returns value before increment (original value).
b = ++a // y = 10, a = 10
b = a++ //y = 11, a = 10

Answer 3

thanks Lord krishna

Answer 4

a++ means post increment and ++a means pre increment.
a++ executes after the statement and ++a executes before the statement.
$b = $a++ here you are assigning a 10 and after the statement incrementing $a by one, that's why you get $b = 10 and $a = 11

Answer 5

thanks

Answer 6

Read this post
https://www.sololearn.com/discuss/223343/?ref=app

Answer 7

try this, and understand how it works :

$a = 10
$b = $a++
echo $a the output is 11
echo $b the output is 10

$a = 10
$b = 20
$c = 10
echo $b + ($a++) the output will be 30
echo $b + (++$c) the output will 31

Answer 8

https://www.sololearn.com/discuss/489143/?ref=app