using cin with char* variables

Question

When trying to use cin with char*, as below, the code does not produce any result:
...
char* word;
cin >> word;
cout << word;
...
What is the right way to get user input for char* type variable?

Answer 1

You forgot the memory allocation.

char* word = new char[20];
cin >> word;
cout << word;

Answer 2

Pls guys, do not read input into a limited buffer without making sure the buffer limit is not exceeded by the read. Don't make any assumptions what you will get as an input.
The input in your example could be arbitrary code of arbitrary length... that might be garbage or binary code that an attacker will later try to get executed... This is an example for code injection.

Answer 3

Code playground says: No output

Answer 4

Shrek is love

Answer 5

@Zen, thanks for the answer, it works!
I also tried it with string operator and found this solution:
string word;
getline(cin,word);
cout<<word

Answer 6

@Stefan, do you mean we should always limit input length when using strings?