why this output comes 4 and why not -4; #include<iostream> using namespace std; int main() { int a=4; int *p=&a; p-= 8; cout<<a; }

Answer 1

p-=8 changes the address of the pointer, not the value of a.

To get -4, replace this line with:
*p -= 8;

Answer 2

"P" is a pointer which contains adderss of variable not value of it! By writing "p-=8" you dont even change the address because if address was changed another value would be resualted in output you can simply write a-=8 or *p-=8

Answer 3

* means value of to get -4 try
*p-=8; //value of p=p-8;