number question

Question

I need to knock off the last digit of any user inputed number, Eg. 50 becomes 5 84884 becomes 8488 and so on, I need help on the codin as I don't know were to begin, thank you.

Answer 1

Divide the number by 10.

Meanwhile, if it's a single digit number then the number itself is the last digit.

Answer 2

User input return a string, so slicing is the best way, as suggested by @J Prak, without need to convert it to string in this particular case:

str_num = input('enter a number: ')
print(str_num[:-1])

Anyway, you may want to verify that the user entry is a valid number, and/or use the 'digitless' number in calculation:

def get_num():
str_num = input('enter a number: ')
try:
num = int(str_num)
except:
print('not valid number!')
return None
return int(str_num[:-1])

num = None
while num is None:
num = get_num()

Answer 3

you can use string slice.

convert the integer to string.
string slice will remove the last character in the string and
again you can convert the string to integer.

>>num = 50
>>print(int(str(num)[:-1]))
>> 5

This will work for both integer and string to knock of the last character.

Answer 4

What Rrestoring faith said
num // 10

Answer 5

Well not just 50, I need it to work with any number

Answer 6

Thank you J Prak, it seems to be working

Answer 7

Thanks visph, haven't thought of that... I will try it out!