What am I missing?

Question

I'm trying to make a single die in C++ using
What exactly is wrong with my code? I'm still new to C++ just trying to learn! Thanks!
#include <iostream>
using namespace std;

int main() {
cout << "Your " << "Number " << "is" << endl;
int x=1;
while(x>6);{x++;}
if(x=1);{cout << "1";}
else(x=2);{cout << "2";}
else(x=3);{cout << "3";}
else(x=4);{cout << "4";}
else(x=5);{cout << "5";}
else(x=6);{cout << "6";}

return 0;
}

Answer 1

Not trying to sound offensive or anything but you can better ask what is right. :)
It'll be a shorter answer.

Don't use ; after while or if, it'll end it.
if(x=1) is an assignment, you want to compare if(x==1)
else doesn't accept parameters, you probably mean else if(x == 2)
you can't stack else's like that either.
the while loop (assuming it was correct) is never entered because 1 > 6 = false anyway
and if the condition was true somehow you'd still not end up with a correct dice

This is all you need to generate a dice roll:

#include <iostream>
#include <ctime>
#include <cstdlib>

int main()
{
srand(time(nullptr));
int dice = rand() % 6 + 1;
std::cout << dice << std::endl;
return 0;
}

Answer 2

x is never greater than 6 so it will never be incremented. It will stay 1. Try while x < 7. Also the syntax is a little ropey. Take another look at the positioning of your curly brackets, and also the number of ;'s (most of the code should be inside the while block)

It seems like you should be using a for loop here too. Do you know how to use those?

I can tell you the answer but i figures you'd want to try and solve it yourself first

Answer 3

Dennis is absolutely right though I'd assume that will probably confuse you. I'm guessing being a newbie, and also my assumption was that you were trying to just print 1 2 3 4 5 6 on the screen. If that is the case use a for loop. If not use Dennis's and try ur hardest to understand / take a look at the libraries he's using and what the code he's using is doing

Answer 4

Thanks Everyone! I appreciate your answers!😀😀