Can anyone plzzz.... explain

Question

int i=1;
printf ("%d",printf("%d", printf ("%d",i)));
what is the answer and plzzz... explain
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Answer 1

In C and C++ the printf's return value is the outprinted number of characters, so the output is 1 and then 1 again and then 1 again so 111 will be printed on the console. :) Hopes it helped

Answer 2

Now the answer is 43 in the first iterate of printf (it's 2 chars) so the output of the second iterate is 2. So 432 will be written on the console :)

Answer 3

Because the number of characters in 43 is 2. Try to look for it like a string "43" as a string has 2 characters so 2 will be printed out in the end.

Answer 4

then what is the answer now
int i=43;
printf ("%d",printf("%d", i));
what is the answer and plzzz... explain

Answer 5

no....dear now answer is 2 whyyyyy