How to calculate with a fractional number proceeded after 0?

Question

I am trying to solve a problem and I know we can't divide or do any Arithmetic with anything that ceils to zero.

Eg: 6/(23/45);

or just show that number. Eg: 23/45;

Now, if you build a calculator or other such code how will you overcome this?

I tried this simple code: https://code.sololearn.com/cl5YfK0mS8RH/

any idea?

Answer 1

It has no problem showing the number it has problem with doing Arithmetic operations with such number.

Eg: I tried double i = (10)/(23/45);

or i = 10 / 0.10;

And as always it gave an Exception in thread "main" java.lang.ArithmeticException: / by zero ;

I can't assure about other languages yet.

Answer 2

I see even after casting into double the big operation is not resulting in right answers.

Got example in that code.

Answer 3

I got the solution.

The problem was especially for fractional numbers after 0.

Solution:
Up cast or down cast.

on code playground, use try catch.

on netbeans it worked all the time even without try catch block.

Answer 4

after arithmetic calculations, how to show exact number, if you get the result such as 0.9

Answer 5

reply :
nop. If you look at the code, it shows double numbers in this formate : 0.0; that means not only int.

Answer 6

Also I tried Bing: showing correct answers.
Try this: ((3 / 9) * (8 / 10)) / (23 / 45) == 12 / 23
and you get this: ((3 / 9) * (8 / 10)) / (23 / 45) == 12 / 23 = True

How other things and calculators are calculating these?

Answer 7

so basically
if the ans is between 1 and 0
it shows as 0.0 right????

Answer 8

here is my solution

check.

https://code.sololearn.com/cJZ8EQ6f36pW/?ref=app

Answer 9

rifat
explain in details once more..
ehat exactly u want to do

Answer 10

i dont do java

but is there no thing to convert int from float..
looks like it prints the answer in int and so its always zero...

Answer 11

compiler varies then