Can anybody tell me y this happening in c language

Question

int main(){
short int a =5;
printf("%d"+1,a);
getch();
return 0;
}

this code only prints d explain me why....
not even the value of a that is 5

Answer 1

Here is a example created by modifying the code

https://code.sololearn.com/cQ6C6WeR099N/?ref=app

Answer 2

"%d" is of type char*, doing "%d"[1] is 'd'
it is also equivalent to *("%d"+1) so "%d"+1 is the address of 'd'

Answer 3

thanks

Answer 4

oh.... nice... thanks u guys are awesome

Answer 5

Your are welcomed ! :)

Answer 6

and what is the difference between %d and %*d

Answer 7

It has meaning for scanf only
Adding the * means that the %d will not be read but needs to be here

Answer 8

😂😂😂

Answer 9

i did
+2
printed POSIX
+45
printed c
+36
printed 6c

😁😂😂😂

Answer 10

😉😂😂😂😂
+21

printed-->
ng : : erase