Can someone help me if someone puts in the wrong operator is still registers as multiplication.

Question

try:
num1 = float(input('Enter number'))
except:
print('Invalid input')

oper = input('-|+|x|/|')

try:
num2 = float(input('Enter number'))
except:
print('inavalid input')

if oper == ('-'):
result = num1 - num2
elif oper == ('+'):
result = num1 + num2
elif oper == ('/'):
result = num1 / num2
elif oper == ('x') or oper == ('*'):
result = num1 * num2
else:
print('invalid operator')

print(result)
https://code.sololearn.com/cSbaV08ZnwE1/?ref=app

Answer 1

Firstly test1 and test2 are never assigned which would throw an error.
But that's not what you're asking about you're asking about why (oper == 'x' or '*') always return true, that's because it converts your '*' into true.

Answer 2

Simply, you should tweak the code:

if oper == 'x' or oper == '*':

Answer 3

It doesn't seem like test1 and test2 were ever used in your program.

You could have just done:

if oper == ('-'):
result = num1 - num2
elif oper == ('+'):
result = num1 + num2
elif oper == ('/'):
result = num1 / num2
elif oper == ('x') or oper == ('*'):
result = num1 * num2
else:
print('invalid operator')

Answer 4

okay I get it now thank you very much

Answer 5

okay I see what you mean. I thought learning this will be easy but it's a lot of tricky stuff in here. so I'm going to be asking you guys for a lot on help. It will be greatly appreciated.

Answer 6

okay I changed it works now thank you